given=
(i=0nΣ(i/n)^(1/sin2x))sin2x* n= 0 , since 1/sin2x≥1 and i/n<=1
what's the answer??
lim x->∞ {11/sin2x + 21/sin2x + .... + n1/sin2x} sin2x
??????
given=
(i=0nΣ(i/n)^(1/sin2x))sin2x* n= 0 , since 1/sin2x≥1 and i/n<=1
what's the answer??
oops sorry, one term inside was n/n, it will give 1 not 0. so answer=1.n=n