limitsssssssss

lim x->∞ {11/sin2x + 21/sin2x + .... + n1/sin2x} sin2x

??????

4 Answers

1
ith_power ·

given=

(i=0nΣ(i/n)^(1/sin2x))sin2x* n= 0 , since 1/sin2x≥1 and i/n<=1

what's the answer??

1
skygirl ·

ans = n.

1
skygirl ·

the options are: 0, infinity, n , and n(n+1)/2.

1
ith_power ·

oops sorry, one term inside was n/n, it will give 1 not 0. so answer=1.n=n

Your Answer

Close [X]