use power limit as manish bhaiya has done
the formula is
limx→af(x)g(x)
where when we find out the absolute form of limit and we get 11/0or 1∞(both are same )
we can write limx→af(x)g(x)=e{f(x)-1}g(x)
use this formula the answer has to come...:P
1) \lim_{x\rightarrow 0} \left\{tan(\Pi /4 +x ) \right\}^{1/x}
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5 Answers
Manish Shankar
·2010-06-25 08:25:51
\lim_{x\rightarrow 0}(\frac{1+tanx}{1-tanx})^x=(1+\frac{2tanx}{1-tanx})^x=(1+\frac{2tanx}{1-tanx})^{(\frac{2tanx}{1-tanx})*\frac{x}{tanx}*\frac{1-tanx}{2}}
Kalyan IIT-K Beware I'm coming
·2010-06-25 18:45:16
Lokesh Verma
·2010-06-26 02:02:37
not unless f(x) tends to 1 as x tends to a...
even then you have to be careful
Kalyan IIT-K Beware I'm coming
·2010-06-26 04:10:42
true nishant bhaiya
but generally this formula is what helps..
there r a few other for power limit....