maxima minima

find min. value of ax2(sin x)2/(xsin x) x belongs (0,pie)

5 Answers

1
ith_power ·

min value doesn't exist.

reason:
as x≠0,π, ax sin x >0. but as x→0 or x→pi, axsinx→0 but≠0.

1
big looser ......... ·

i am sorry its (9x2sin2x+4)/(xsin x)

1
Ashish Sharma ·

Hint: k=x.sinx

1
big looser ......... ·

i am still not getting plz help...............

1
Rohan Ghosh ·

as x belongs to (0,pie)
xsinx is always +ve

this expression can be written as

9xsinx+4/xsinx

applying A.M>G.M
we get the min. value as = 12

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