The minimum value of mod of(sinA + cosA + tanA + secA + cotA + cosecA) is 2√2-k.Find k
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3 Answers
1357sinx+cosx+(1+xinx+cosx)/sinxcox
take sinx+cosx=t
it becomes
t+2(1+t)/(t2-1)
t+2/(t-1)
differentiate it to get the critical points
1357its correct
differentiating it we get
1-2/(t-1)2=0
it gives, t=1±√2
but -√2≤t≤√2
so t will be 1-√2
so we get
1-√2-√2=1-2√2
if we take mod it becomes
2√2-1
263Sir but then the ans. is coming as 2√2+1.So k=-1.But it is 1.Might be the question is wrong