1differentiate both sides
\int f(x)sinxcosx dx = \frac{1}{2(a^{2}-b^{2})}log (f(x)) + c
THEN f(x) = ????
ans GIVEN ----> \frac{1}{a^{2}sin^{2}x + b^{2}cos^{2}x}
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5 Answers
1f ( x ) sin x cos x = \frac{1}{ 2 ( b^2 - a^2 ) } . \frac{1}{f( x ) } . f' ( x )a
2 ( b^2 - a^2 ). sin x cos x = . \frac{1}{f( x ) } . \frac{1}{ f ( x ) } . f' ( x )
now integrate
1are eure who said u this
integration is antiderivative
therefore differentiatin a antiderivative gives back that function it self
