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DOUBT
f(x)=√ax2+bx.FInd all possible values of 'a' such that there exist at least one positive value of 'b' for which both domain and range of f(x) lie in same set
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5 Answers
4ax2 + bx ≥ 0
either x≥0 & x≥ - b/a
or x≤0 & x≤ - b/a
Case i : x≥0 & x≥ - b/a
b>0
a can be <or > 0
case ii : x≤0 & x≤ - b/a
b>0
again a can take any values depending on x
24trying to understand ur soln....but what came to my mind was 3 cases
a>0
a=0
a<0
i solved this way and got something...but i need soln from others tooo