put x= tanθ
dx = sec2θ
1 + x2 = sec2θ
integral reduces to ∫log ( 1 + tanθ) dθ
i think this cannot be solved .
u forgot to tell the limits
put x= tanθ
dx = sec2θ
1 + x2 = sec2θ
integral reduces to ∫log ( 1 + tanθ) dθ
i think this cannot be solved .
u forgot to tell the limits