1@tapan cud u post the method i made two series
Q1\lim_{n\rightarrow infinity}(\frac{1}{n^{100}}\sum_{r=1}^{n}{r^{99}})
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67 Answers
1so after all this
subhash's post should be the correct answer.....
chalo khatam hua
ok bye
1if a is a maximum of f(x)=\frac{1}{8}(6x^{2}-x^{3}-16)
and r= \lim_{x\rightarrow 0}\frac{1-cosx}{x^{2}}
S = a + ar +ar2.........∞
find √S
x tendind to inf mein toh r = 0 or question ki tabahi ho jayegi..
so this ought to be the correct question
1even now it ranges up to ∞ @mani n phillip guys this equation is not having finite maximum value as its ranging up to ∞ correct me if i m wrong
1cubic eqn hai quad nahi manipal (waise bhi is quadratic ka max kaha se niklega)
mera upri post dekh..
pichle page mein usse koi mistake ho gayi hai
pehle usne bhi cubic hi likhi thi
1f(x)=\frac{1}{8}(6x^{2}-x-16)
maybe im sleeping but was there x cube somewhere
or is this the question
i thot it was
f(x)=\frac{1}{8}(6x^{2}-x^{3}-16)
otherwise how can it have maximum
21Q3
L = 3/2;
now solve the rest...... eure mera ans sahi hai kya?
24For those like me who didnt know about Riemann sum::
http://en.wikipedia.org/wiki/Riemann_sum
earlier i knew that this method was called limit as sum.....[3][3].now i know the real name..[1][1]
24ok ok sorry friends............maybe i was sleeping when i edited the question....
but it is x3 in f(x)
Solution::
Max value of f(x) at x=4
=>Max value f(x)=2
=>a=2
Solving the limit we get r=1/2
=>S=2/(1/2)
=>S=4
=> √S=2
62Q3 is easy guys
just multiply and divide by 1-1/3
you will get
\frac{1-1/3^{2^n}}{1-1/3}
limit of this will be 3/2
hence 2L=3 which is prime
I dont what we mean by minimum and maximum value!
I guess this is always increasing so max will be 3/2
min will be 4/3!
24oops sorry again maybe i forgot to edit that.......it is lim x→0
TMH made a big error in this question[2]
11yaar sidhi si baat hai
limx---->0 pe sinx ka graph
suggestkarta hai ki yeh
as x-->0 yeh bhi 0 ki taraf hi move kar raha hai
but ∞ is not a value neither it is number
so its value SHOULD NOT be defined at ∞
I THINK PHILIP WAS PERFECT IN FRAMING THE QUESTION IN #49
21Mani : Yeh mera bhi doubt hai......\\
L = (1 - COS(x))/x2
lim x ---> ∞
reduces to 2sin2(x/2) / x2
isse aage kaise karna hai mujhe nahi aata........ [2]
I WUD B GLAD TO KNOW HOW TO SOLVE THIS un.....
and ya pl. remember the questn says x---->∞, not 0 coz oderwise it wud b a cakewalk!!!
11EUREKA SAID IN #6O THAT
ok ok sorry friends............maybe i was sleeping when i edited the question....
but it is x3 in f(x)
Solution::
Max value of f(x) at x=4
=>Max value f(x)=2
=>a=2
Solving the limit we get r=1/2
=>S=2/(1/2)
=>S=4
=> √S=2
MY QUESTION IS
IF X---->∞ HOW COULD WE GET r=1/2?????????
1@mani either i am [7][7] or u are [7][7] and we both are making lot of [7][7][7][7] together
@eureka
[6]happens
lez do the rest of 'em now
11philip said in #54
ARREY WHEN WE dont know which or rather wat is the correct question how can u keep on guessin evrything girls..
leave this for now... until eureka comes
othewise i announce ( forgive the expression)
that post 49 is correct question and subhash's soln is good
TO WHAT ABOUT #28
?????????????
1at last someone came in a mood to finish it off
thaans integra....wats in a mane.. oops name..(sorry was a mistake but it was so funny:D)
i was going mad