Q1\lim_{n\rightarrow infinity}(\frac{1}{n^{100}}\sum_{r=1}^{n}{r^{99}})
11#25 subash said
answer for Q4 is 1
for the limit in
r=(2sin2x/2)/x2
it comes out to be 1/2
and a=2 which is also pretty easy to find
so answer 1
bhai itni deer se mein chup baitha hoon kyunki
x------------->∞
yeh mazaak nahin hai [2]
its not x------------->0
24oooooooo..........thanks philip.....maine kabhi is par socha hi nahin.....sirf result rakha thaa dimaag mein.......ab tere se iska proof bhi sikh liya........thanx.
1ure welcome eureka [1]
btw no thanx and sorry b/w friends please
24okzzz........but u helped me in a big way.............i came to know about that result 2 dayz back......and i didnt spend time deriving it.....just learnt it.......
