oh nice....
Just think how many times y=2x+3x+4x
and y=5x
their derivatives will help which one is increasing at what rate...
Also plotting some imp points will help.......
If this does not help....Plz tell.....
oh nice....
Just think how many times y=2x+3x+4x
and y=5x
their derivatives will help which one is increasing at what rate...
Also plotting some imp points will help.......
If this does not help....Plz tell.....
answer is 1 solution on substituting 1 2 and 3 you get
on substitutong 1 : 9 on lhs and 5 on rhs
on substitutong 2 : 29 on lhs 25 on rhs
on substitutong 3 : 99 and 125
in first 2 cases lhs > rhs
3 case lhs<rhs
clearly the graphs will intersect in this region and never intersect again.
(between substituting 2 and 3)
the ans is 1 sol.
i did it by takinh 5x to the rhs and then divided the whole expression .by 5x
yes naman.. that is a good way too :)
I would say a much better way
but i am not sure whether (2/5)x+(3/5)x+(4/5)x will have graph similar to ax.
it will be the sum of these three.. and u have to check the derivatives to see the behaviour.. i am sure it wont be such a difficult ask!
and btw graphs is used to find some short cut.. so it gives u a much faster way to solve..