1)
f (x) = ax2 + bx + c; a, b, c ∈ R & a ≠0
g (x) = dx2 + ex + f; d, e, f ∈ R & d ≠0
given real part of both eqn is equal
root of f(x)=0 is -b±√b2-4ac2a
root of g(x)=0 is -e±√e2-4df2d
since real part is equal
-b2a = -e2d
bd=ae
hence option (b) correct