pl give a hint

da pblm is

25n+1/4
{ 2x+3}
let f(X)=∫ e dx , where {x}denotes da fractional part ...da qn is easy but i dunno wer i went wrong
3

3 Answers

62
Lokesh Verma ·

25n+1/4
let f(X)=∫ e{ 2x+3}
3

the period of the function inside the integral is 1/2

for every 1/2 increase in x the power will start to repeat

also, { 2x+3} = {2x}

so this is basically

2(25n-3). integral from 0 to 0.5 of the given expression + 1. integral from 0 to .25 of the given expression. :)

62
Lokesh Verma ·

yup i too felt that there was some issue.. but solved it with what i felt the best guess.

1
AARTHI ·

its da qn i don remember wer i saw dat but da qn is rite

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