33Why this was in calculus...[3]
RANGE OF 16-x C 2x-1 + 20-3x C 4x-5 is
(a) [728 , 1474]
(b) {728 , 1474}
(c) {0,728}
(d) none
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5 Answers
62what i can see on this one is that
x<=6, x>1
So that this becomes kind of simple?
what i can also see is that
(16-x)=(20-3x) + 2x+4
(2x-1) = (4x-5) + 2x+4
Though this does not help me on the first look.. does it help u?
62btw from the options that you have given it seems to me that the correct answer will be (B)
Dont know why..just gut feeling. (because d is generally not the correct answer)
The range set has a maximum cardinality of 6
So it cant be a)
also, c) is not possible because 0 is an option there!
62x=2 => 14C3+14C3
x=3 => 13C5+11C7
it wont be defined for x>3 either..
so it will be a 2 set... !!!
62yaar the solution was an anticlimax.. i had thought that this wud have something interesting as the solution :D
