231.5 is not satisfying
1.5 -1 / 1.5 = 1/3
2{1.5} = 1
1/3 -1 < 0 so not in domain
ur question is (x-1x-2{x} )1/2 or (x-1x-2{x} )1/2
FIND THE DOMAIN OF √(X-1)/X-2{X} ?WHERE {.} DENOTES.FRACTIONAL X??
ACORDING TO THE GIVEN ANSWER IS- (-∞,0)U(0,1]U[2,∞)..
BUT I DONT THINK THE ANWER IS CORECT BCOZ U TAKE ANY POINT IN [1,2] THE POINT WILL SATISFY THE GIVEN FUNCTION FOR EXAMPLE I TOOK 1.5,1.6,1.00009,ETC..
PLZ HELP ME OUT..ITS FOUR MARKS OBJECTIVE QESTI0N..I HV TO CLAIM MY MARKS AT 12 PM PLZ HELP
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6 Answers
23
341Write it as \sqrt{\frac{x-1}{[x]-\{x\}}}
So either x≥1 and [x]>{x} or x<1 and [x]<{x}
x≥1 and [x]>{x} is true for [1,∞)
If 0≤x<1, then [x] = {x} and is not admissible
If x<0, then we do have x<1 and [x]<{x}. So, [-∞,0) is also a subset of the domain.
Hence the domain is just [-∞,0) U [1,∞)
Another way to express it is as \mathbb{R} - [0,1)