the solution anyone???
P(x) be a polynomial of degree at most 5 which leaves -1 and 1 upon divison by (x-1)3 and (x+1)3 respectively then
1)no of real roots of p(x)=0
a)1 b)3
c)5 d)2
2)the maximum value of y=p"(x) can be obtained at x=
a)-1/√3
b)0
c)1/√3
d)1
3)the sum of pairwise product of all roots(real and complex) of p(x)=0 is
a)-5/3
b)-10/3
c)2
d)-5
-
UP 0 DOWN 0 0 4
4 Answers
eragon24 _Retired
·2009-12-02 05:35:12
this q was discussed here na-----http://targetiit.com/iit-jee-forum/posts/try-this-12468.html----is of hongkong national olymp----and it then came in fiitjee pt1 in 2008