prove

prove that
2\pi <sin xx<1

for x e (0,\pi 2)

6 Answers

11
Tush Watts ·

Ans) Let f(x) = sinxx
Since f(x) is dec in the interval (0 , ∩/2)

Therefore, f(0) > f(x) > f (∩/2)
That implies, 1 > sinxx > 1∩/2 = 2 / ∩

1
Kaustab Sarkar ·

ths toh i know

but how to prove that f'(X)<0 for proving it to be dec func

how to prove that (xcosx-sinx)/x2 is <0

24
eureka123 ·

x2>0 for x>0
so only thing left to prove is xcosx-sinx<0

which is true iff sinx>xcosx
=> tanx>x

which is true ...(See graph)

11
Devil ·

derivative of tanx is sec2x, which is ≥1.

1
Kaustab Sarkar ·

ok thanq everyone... i got it :)

1
Kaustab Sarkar ·

one more

prove taht f(x)=(1+1x)1/x is monotonically increasing in its domain

and draw its graph also :)

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