1 Answers
Lokesh Verma
·2010-08-10 11:21:25
The given expression is equal to
(2x-a)2-2a+2
The first term has to be greater than or equal to zero...
It is zero at x=a/2
if a/2 lies between 0 to 2 then the minimum value will be 2-2a=3 ie a=-1/2 which means a/2 does not lie in the interval 0 to 2...
Hence there is no value of x in the given interval