Ration of definite Integral

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\hspace{-16}$If $\mathbf{I_{1}=\int_{0}^{1}(1-x^4)^7dx}$ and $\mathbf{I_{2}=\int_{0}^{1}(1-x^4)^6dx}$\\\\\\ Then $\mathbf{\frac{29}{4}.\left(\frac{I_{1}}{I_{2}}\right)=}$

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rishabh ·2012-03-12 04:31:10

use by parts for I₁ => I₁ = 28 âˆ« (1-x⁴)⁶ . x⁴

=> I₂ - I₁28 = I₁
=> I₁I₂ = 2829 \Box

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Ration of definite Integral

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