1No value for K in this case
\hspace{-16}$\textbf{For what real value of $\mathbf{k}$ for which the equation}\\\\ $\mathbf{x^3-2x^2-2010x+k=0}$ \textbf{has no Real solution.}
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3 Answers
62k=-x3+2x2+2010x
this is a cubic so continuous
near + infinity, the value of k is -infinity
and near -infinity k is + infinity
so it is evident that this has a real root for all values of k!
hence there is no real k for which this has no solution.
262it is a polynomial of odd degree.
hence there has to be at least one real root !!
