let R be a rectangle of length 2 and breadth 1.Consider ny quadrilateral which has one vertex on each side of R. a,b,c, and d denote the lengths of the sides of the quadrilateral..
the value of 't' satisfying a2+b2+c2+d2=-t2-4t+1 is equal to
a) -2
b) 1
c) 3
d) -1
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1 Answers
625<=a2+b2+c2+d2<=10 (How?!)
So
4<=-t2-4t<=9
t=-1 gives -t2-4t = 3
t=1 gives -t2-4t = -3
t=-2 gives -t2-4t = 4
t=3 gives -t2-4t = -21
only one of these fall in the range! :)
