Q2)When we shift the graph of(x) through a towards left, we transform f(x) to f(x-a).Say funct be y=x.If I change it to y=(x-1). first f(2)=2, f(3)=3 f(4)=4.Now (3)=2 f(4)=3 f(2)=1.this means initially, 2 was the value for 2 but now its the value for 1(i.e 2-1).Similarly initially, 3 was the value for 3 but now its the value for 2(i.e3-1).If we do like this the graph shifts to the left.this is in complete contrast with the first statement.plzzzzzzzz explain.
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1 Answers
49seemingly ur concepts are a bit wrong in your statements...
u say that f(x) is a function
and suppose f(0)=a
next u perform the operation f(x-k)
in doing so, the function's graph shifts not towards left but towards right
look this is because, the function takes the value a when the input is 0 i.e. f(0)=a
this shows function f(x-k) can take value a when x-k=0 i.e., x=k
so the values of final curve takes values corresponding to the initial curve at a distance k towards the right of the the x-coordinate of initial curve.
i.e i mean to say that, in the given function y=x
when we transform y=x'-1 (i am using x' to differentiate from x of the original function)
we get x=x'-1
→x'=x+1 signifying a shift towards right!!
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hope u got it now!!:)