put 5x2+49 =t to get,
12.515∫ (t-49)14t17 dt . t=49->∞
=> expanding by binomial theorum and integrating we get
=> 12.515 (-14C0.t-22 + 14C1.49.t-33 -...........)
=> now putting limits and using limit t->∞ t-k = 0
=> also we get (49)-2 common in each term,
=> 12.515.492 Σ 14Cr(-1)rr+2
u cn do it frm here