don't you think it would be tedious to do that and then cancelling the terms ....i think taking log first and then differentiating will help...
4 Answers
Dr.House
·2009-05-23 02:02:51
px^{p-1}y^{q}+x^{p}qy^{q-1}\frac{dy}{dx}=(p+q)(x+y)^{p+q-1}(1+\frac{dy}{dx})
now i think u can rearrange the terms to get \frac{dy}{dx}
Shriya
·2009-05-23 07:33:02
MATRIX
·2009-05-23 07:38:47
just take log and do naa.........u'll get..........
plogx*qlogy=(p+q)log(x+y)
u'll get remaning by differentiating.........