SIMPLE ONE THOUGH....

MULTIPLE ANS QS

1) Lt x--->2 [(f(x) -9) / (x-2)] = 3

Then Ltx-->2f(x) is ?

(A) 2 (b)5 (C) 9 (D)12

11 Answers

11
Devil ·

9.

11
Devil ·

Assuming u meant lim_{x\rightarrow 2}f(x)=....

1
akari ·

yes f(x)→9 then only we get 0/0 form

4
UTTARA ·

2) f : R---->R is defined as f(x) = { x^2 +kx+3 for x>=0

{ 2kx+3 for x<0

If f(x) is injective then 'k' =

(A) 2 (B)5 (C) 9 (d)12

4
UTTARA ·

3) log 1.5[cot-1x - sgn(ex) ] = 2

Does it have real solutions???

106
Asish Mahapatra ·

(3) yes log will be defined when cot-1x > 1 (=sgne^x)

for which there are real solutions as range of cot-1x is [0,3.14]

106
Asish Mahapatra ·

(2) as the parabola is concave upward, and if k<0 then the st line is downward and the parabola is upward so it wont be one-one

sory my mistake.

now after x=0 f'(x) > 0 for the parabola

=> 2x+k>0 for all x>0

=> k>0

so a,b,c,d

4
UTTARA ·

@Ashish : This is my explanation for 2nd qs which's contradicting 3 of u're options

f(x) is injective so the quad eqn shud have no distinct roots

So D≤0

k2 ≤ 24

So ans shud b only A na?

106
Asish Mahapatra ·

no D need not be less than zero, what if both the roots are less than zero?? and the value of f(0) = 3 then the function will be injective wouldnt it?

4
UTTARA ·

Ok fine I agree with ur ans

341
Hari Shankar ·

for the first one, when you say it should be 0/0 form, you are assuming

1. continuity at x=2

2. differentiability at x =2

3. and Ltx→2 f'(x)

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