whether its a fight or not i havent been in it
1)[x]+[y]=x
2)y=[x]-[x-(1/2)]
3)[x+y-2]-[x-1]=0
where [ ] is GINT
Explain the steps toooo
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21 Answers
arey i am weaaaaaaak in box function re... see upar!!
or else i wud have loved to help :)
YUP its a fight going on .............AND NOBODY CARES FOR POOR EUREKA WHO IS SO POOOOOR IN GRAPHING AND WANTS TO LEARN TO QUICKLY FROM HIS FRIENDS.............plzzzz sky atleast u help me,......
Everyone is so busy fighting among themselves that they FORGOT to read this line in question......
""Explain the steps toooo""
i think abhirup's one is correct... am also getting dat only...
wrong bhi ho skta hai :( [3]
and my last was wrong only ....
areyyyy saare wrong hi hai :(
1,2,3 sab :(
this above one will be the answer for part 1 ..
where you will have to consider one thing...
the top most points on the curve is not lthere.. i mean y=+1
1) only the point (0,0) .
[y] = {x}
{x} is only for[0,1) and [y] = all integers .
these two are satisfied for only (0,0).
How did u get it sky? Why are there dotted lines?
Graph for [x] is
And graph of [x-1/2] is
DONT MIND THE SCALE
So shouldn't it be the difference obtained by superimposing the graph?
GRAPH (WHICH I HOPE IS CORRECT[3]) IS IN MY NEXT REPLY[4]
So far good but slight mistake..
YOu said that the only possible solns were
{x}=[y]=0
Now the last interpretation is incorrect
The answer should be (n,0) where n is an integer!