Sketch it

1)[x]+[y]=x
2)y=[x]-[x-(1/2)]
3)[x+y-2]-[x-1]=0

where [ ] is GINT

Explain the steps toooo

21 Answers

62
Lokesh Verma ·

1
skygirl ·

arey i am weaaaaaaak in box function re... see upar!!

or else i wud have loved to help :)

11
Subash ·

whether its a fight or not i havent been in it

24
eureka123 ·

YUP its a fight going on .............AND NOBODY CARES FOR POOR EUREKA WHO IS SO POOOOOR IN GRAPHING AND WANTS TO LEARN TO QUICKLY FROM HIS FRIENDS.............plzzzz sky atleast u help me,......

1
skygirl ·

fighting [7] [7]

[3] [3]

24
eureka123 ·

Everyone is so busy fighting among themselves that they FORGOT to read this line in question......

""Explain the steps toooo""

1
skygirl ·

i think abhirup's one is correct... am also getting dat only...

wrong bhi ho skta hai :( [3]

11
Anirudh Narayanan ·

None of the replies have green backgrounds?

1
skygirl ·

and my last was wrong only ....

areyyyy saare wrong hi hai :(

1,2,3 sab :(

1
skygirl ·

3. )

62
Lokesh Verma ·

this above one will be the answer for part 1 ..

where you will have to consider one thing...

the top most points on the curve is not lthere.. i mean y=+1

1
skygirl ·

1) only the point (0,0) .

[y] = {x}

{x} is only for[0,1) and [y] = all integers .

these two are satisfied for only (0,0).

11
Anirudh Narayanan ·

how do you plot y+x-2?

11
Anirudh Narayanan ·

That's what I've posted isn't it?

13
Двҥїяuρ now in medical c ·

2)

11
Anirudh Narayanan ·

[7]?????[7]

11
Anirudh Narayanan ·

(2)

62
Lokesh Verma ·

none of u noticed..

my answer aboev is incomplete!

11
Anirudh Narayanan ·

How did u get it sky? Why are there dotted lines?

Graph for [x] is

And graph of [x-1/2] is

DONT MIND THE SCALE

So shouldn't it be the difference obtained by superimposing the graph?

GRAPH (WHICH I HOPE IS CORRECT[3]) IS IN MY NEXT REPLY[4]

1
skygirl ·

2.)

62
Lokesh Verma ·

So far good but slight mistake..

YOu said that the only possible solns were

{x}=[y]=0

Now the last interpretation is incorrect

The answer should be (n,0) where n is an integer!

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