1how???????????????
which of the foll. is differentiable At x=0?
a)cos([x]) - [x]
b)sin([x]) +[x]
c)sin([x])- [x]
d)cos([x]) + [x] where[.] represents modulus.
pls give reason.
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5 Answers
11use the basic definition to find that:
RHD ofsin\left|x \right|-\left|x \right|=
=>\lim_{h->0}(sin\left|h \right|-\left|h \right|)-(0-0)/h yaar h poore ke niiche hai
=>\lim_{x->0}sinh/h-h/h=1-1=0
sin(\left|h \right|-\left|h \right|)-(0-0)/-h =>\lim_{x->0}sinh/-h+h/h=-1+1=0 f(0)=sin(\left|0 \right| -\left|0 \right|)=0
sosin\left|x \right|-\left|x \right| is differentiable at x=0
the answer is (C)
try to find for others also so it would not come
yaar i know this came in iit and was a tough one
but never forget to use the basic definition in case of trouble!!!!!!!!!!!
13these functions can be in GOD
they are nice....
