If a, b, c belongs to R satisfy 7a/3 + 3b/2 + c = 0, then atleast one root of the equation ax2+bx+c = 0 lies between
a. (3, 4)
b. (0,2)
c. (3/2, 2)
d. (1, 3/2)
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1 Answers
106let F(x) = ax3/3 + bx2/2 + cx +d
F(2) = a/3+b/2+c+d = F(1)
So, from Rolle's thm
there is one root of f(x) in (1,2)
