Tangents and Normals

Prove that the segment of the normal to the curve x=2asint+asintcos²t; y=-acos³t contained between the coordinate axis is equal to 2a!!!!!!!!!!!!!!

1 Answers

Find equation of normal, get the intercepts and take the root of the sums of their squares ie âˆš(a²+b²) and u'll get what u want. :)

P.S: U see, i'm a little weak in proofs in geometry. Sorry, i couldn't give u the proof :(

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