We say \lim_{x\rightarrow 2}x^{2}=4.
Let the limit be L .
So is L=4 or L<4 or L> 4 ?
Having addressed this question, can we conclude on the following statements:
1) \lim_{x\rightarrow 0}\frac{\sin x}{x}=1 \Rightarrow \sin x = x \Rightarrow \lim_{x\rightarrow 0}\frac{x}{x}=1
2) \lim_{x\rightarrow 0}\frac{\ln (1+x)}{x}=1 \Rightarrow \ln (1+x) = x \Rightarrow \lim_{x\rightarrow 0}\frac{x}{x}=1
I'd hope some expert clears this confusion with some detailed explaination!
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1 Answers
Debosmit Majumder
·2011-07-03 12:12:46
limits are exact....as nishant sir has told us
so L shud be exactly equal to 4