Tough DI

10∫19 (sin x / 1+x8 ) dx <

A. 10 -10
B. 10 -9
C. 10 -8
D. 10 -7

4 Answers

11
Tush Watts ·

Ans is (c) 10 -8????/

11
Tush Watts ·

Ans) I = | 10 ∫19 (sin x / 1+x8 ) dx | ≤ 10∫19 (sin x / 1+x8 ) dx

(Using property | a ∫ b f(x) dx | ≤ a ∫ b f(x) dx

Since |sinx| ≤1 for x≥10

Therefore, |sinx / (1+x 8) | ≤ 1 / |(1+x 8) | ...........(1)
10 ≤ x ≤ 19
so, 1+x8 > 10 8
1 / (1+x8) < 1/ 10 8 or
1 / |1+x 8| < 10 -8 .........................(2)

From (1) and (2),
|sinx / (1+x 8) | ≤ 10 -8 is fullfilled
| 10∫19 (sin x / 1+x8 ) dx | < 10∫19 10-8 dx

So, |10∫19 (sin x / 1+x8 ) dx | < (19-10) 10 -8 < 10-7
Therefore, the true value of the integral = 10 -8

11
Gone.. ·

Tushar you have got the ans..saw your working its.its (D)

10∫19 (sin x / 1+x8 ) dx < 10-7

The true value of the integral ≈ 10 -8

I found same problem solved by I.A.Maron...

Same as yours but summarized..im posting that below.

11
Gone.. ·

Since |sinx| ≤1 for x≥10

|sinx / (1+x 8) | ≤ 10 -8 is fulfilled

So, |10∫19 (sin x / 1+x8 ) dx | < (19-10) 10 -8 < 10-7

( The true value of the integral ≈ 10 -8 )

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