question is as mentioned by SR (SEE DOWN)
ANS ----> cot A { log sec(x+A) - log sec x}
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there is no x besides tanx ...
since ans is same as given by manmay
\int \left( 1 + \frac{sin x . sin ( x + A )}{cosx . cos ( x + A) } \right)
\int \left( \frac{cosx . cos ( x + A ) + sin x .sin ( x + A) }{cosx . cos ( x + A ) } \right)dx
\int \left( \frac{cos ( x + A- x ) }{cosx . cos ( x + A ) } \right)dx
cos A \int \left( \frac{dx }{cosx . cos ( x + A ) } \right)
further simplify
cot A \int \frac{sin A . dx}{cosx . cos ( x + A ) }
cot A \int \frac{sin ( x + A - x) . dx}{cosx . cos ( x + A ) }
cot A \int \left( \frac{sin ( x + A ) . cos x}{cosx . cos ( x + A ) }- \frac{cos ( x + A ) .sin x}{cosx . cos ( x + A ) }\right )dx