Use:
∫sin(mx)cos(nx)dx
=∫(emx-emx) (enx+enx)2idx
Anurag Ghosh kk....thanxxxxx
Upvote·0· Reply ·2013-08-05 04:57:48
Can anyone plz explain the use of complex numbers ( de-moivre's theorem) in finding out the integral of type
∫sinmxcosnxdx , where both m,n are positive integers.
Use:
∫sin(mx)cos(nx)dx
=∫(emx-emx) (enx+enx)2idx