If 1021 molecules are removed from 200 mg of CO2 then the number of moles of CO2 left is
2.88 x 10-3
1.66 x 10-3
4.54 x 10-3
1.66 x 10-2
Your Answer
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Correct Answer
a
please show me the calculation.
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1 Answers
Rajiv Agarwal
·2014-03-13 04:19:02
44 gm of CO2 contains 6.023 x 1023 molecules
200 mg of CO2 contains = (200x10-3/44) x 6.023 x 1023 molecules
Now, from this number, subtract 1021
This should give you the answer.
Solve and let us know :)
- Rohit Ghosh BUT IN THE QUESTION IT IS SAID TO 1021 MOLECULES N0T 10 TO THE POWER 21.Upvote·0· Reply ·2014-03-14 22:40:22
- Rohit Ghosh ANYWAY THANK YOU FOR THE CALCULATION