Let x1m+y1n+z1p = k.
So, x=km; y=kn; z=kp
xyz=1
→kmknkp=1
→k(m+n+p)=1
→m+n+p=0 if k≠1.
If k=1, m+n+p can have any value, including 0.
- Sayantan Hazra even if k = 1, (m + n + p)can be zero........ :)Upvote·0· Reply ·2013-06-27 05:04:34
If x(1/m)=y(1/n)=z(1/p) and xyz=1 , find m + n + p
Let x1m+y1n+z1p = k.
So, x=km; y=kn; z=kp
xyz=1
→kmknkp=1
→k(m+n+p)=1
→m+n+p=0 if k≠1.
If k=1, m+n+p can have any value, including 0.
Km+n+p=11=10
So, m+n+p=0 or 1,