k1/x+1/y+1/z
=k2*3*1/6
=k1
so,1/x+1/y+1/z=1.
I GOT 1.IS IT WRONG?
- Sayantan Hazra Yes, it is wrong.......how did you put (1/x) = 2 ??? and similarly the values of 1/y and 1/z ??
- Rohit Ghosh I ADMIT MY GUILT.
If 2^x=3^y=6^-z,then what is the value of 1/x+1/y+1/z? How should I do this ?
I have got 1/x+1/y+1/z=0. Is this correct?
k1/x+1/y+1/z
=k2*3*1/6
=k1
so,1/x+1/y+1/z=1.
I GOT 1.IS IT WRONG?