oh no...that must be (a)...u may substitute any value of n...and then check it...
u will get that its always divisible by at least 6...
so,,(a)...
If n is a natural number,n^2 x 6n is always divisible by
a)6 only
b)12 only
c)6 & 12 both
d)18 only
How will I solve this problem?
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3 Answers
Astha Gupta
·2013-10-17 09:39:38
Angikar Ghosal
·2014-05-11 01:34:32
n2 * 6n = 6n3
6n3 is always divisible ny 6, but may not be divisible by 12 or 18.