Two circles touch externally at P and AB is a common tangent to the circles. Then LAPB is equal to .......
(A) 300
(B) 450
(C) 600
(D) 900
62There has to be more info about A and B...
and also aobut the common tangent..
Hopefully by athe way of an image or otherwise..
the common tangent if it is touching the cirlces at the common point then this angle is 180 degree
A and B probably lie on the two circles
In that case, the answer is going to be different.
36@Nishant sir -> But this was what the question said in the ABD Book for class x....!
Well sir, i think the question is quite okay....!
Construction : We join P with AB at M and P with A and B
Now, we know that tangents from and external point are equal and so....
AM = PM and BM = PM
=> AM = PM = BM
=> LAPB = 900
This is how i worked it out. :D :D