3910001000 = x
=>1000 log1000 = logx
=>1000 * 3 = logx
=>x = 103000
1001999 = y
=>1001 log999 = logy
=>1001 * 2.99 = logy
=>3002.56 = logy
=>y = 103002.56
x < y
9 Answers
3939Ohhh lol I didn't see the section...graying out the solution :P
62how do you know that log 999 is 2.99?
Even if you do using the log tables, in the exam hall you will not be given those :P
39I used log tables to find that
Really? I guess log works for CBSE only...
Now that's a real worry.
21bino will do the work......but bino is not in 9th- 10th syllab i guess[3]
62yup.. binomial is needed
I will have to think of something more basic..
My wrong to have posted it here!
1no prob nishant sir
(1001)^{999}=(1000+1)^{999}=^{999}C_01000^{999}+^{998}C_11000^{998}+...+^{999}C_{999}
>1000^{999}+1000^{998}+...+1000^0=\frac{1000(1000^{1000}-1)}{999}>1000^{1000}
