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an electric bulb rated 50W at 100V is used in a circuit having a 200V supply. What resistance R must be put in series with the bulb so that then bulb delivers 500W?

#Physics #Class VII-X Physics

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Pratyay Patra ·2014-01-24 06:25:38

TH ANSWER IS 10

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Pratyay Patra ·2014-01-24 06:25:41

TH ANSWER IS 10

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Astha Gupta can u show how did u get dis answer?
Upvote·0· Reply ·2014-01-25 01:56:56
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Bunnie Boy ·2017-09-01 13:11:26

I=P/V

I=500/10=5A

Resistance of bulb,R1=100/5=20 ohm

Resistance,r to be connected in series,

5A=200/R1+R2

R1+R2=200/5

R1+R2=40

20+R2=40

R2=20 ohm

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Anonymous I=500/100 instead of 500/10
Upvote·0·2017-09-01 13:14:03
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Bunnie Boy ·2017-09-01 13:12:41

This answer is for 500W not 50 W

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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