3D-3

no of planes that are equidistant from four non-coplanar points is :

a) 3 b) 4 c) 7 d) 9.

visualised the situation and answered...

but someone give me a 'nice' method ... in the sence a 'way' to actually 'solve' ...

7 Answers

39
Dr.House ·

aaj kya 3-d ka barsaat ho raha hain?

21
tapanmast Vora ·

NIshant Sir, has already solvd this on the forum i guess..........

Ans must be 4.

I'll get u the link soon

24
eureka123 ·

7........[12]

1
skygirl ·

no answer is 7 tapan...

11
Anirudh Narayanan ·

Three of the 4 points will lie on a plane. So the plane equidistant from the plane (3 points) and the 4th point is the one passing midway between the plane & point and parallel to the plane. Ways to choose such points are 4C3 (=4)

So why is 4 the wrong answer?

62
Lokesh Verma ·

anirudh sky just told me..

I missed a case.. when we could have 2 points on one side and 2 mor eon the other

so then it wud be 4C2/2+4C3=7

11
Anirudh Narayanan ·

ohhh!!! ok bhaiya and sky. Thanx for the clarification [4]

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