v = u + at
a= (v-u)/t
v2 =u2 +2as
s= v2 -u22a
s=(v+u)(v-u)2a
s=at(v+u)2a
s=(v+u)t2
A train moving with constant acceleration takes t seconds to pass a certain fixed point and the front and back end of the train
pass the fixed point with velocities u and v respectively. Show that the length of the trai is (u+v)t/2
v = u + at
a= (v-u)/t
v2 =u2 +2as
s= v2 -u22a
s=(v+u)(v-u)2a
s=at(v+u)2a
s=(v+u)t2