again parabola

given a parabola as:
x=at2+bt+c and
y=a't2+b't+c'.
..........so find the latus rectum..???
(this is objective question.. i dun have the options r8 now... so, sorry.)

9 Answers

33
Abhishek Priyam ·

so its objective....

62
Lokesh Verma ·

for an objective question, i think this will be far simpler by just putting the conditions like

(at2, 2at)
or (2at, at2)

and checking the repective latus rectum

but right now this doesnt strike my mind immediately :(

62
Lokesh Verma ·

it is like taking different cases.... and eliminating some of the useless terms... i hope u realise this trick..

if u could post the options, i am sure we can eliminate some of the choices even without any calculations

1
skygirl ·

yup i understand...
but r8 now i too dun have the solns....
i will ask and post in as soon as possible....

11
Shailesh ·

This is good question.. pls post something on this.. skygirl.

1
skygirl ·

i willl surely...
i will post the options tomorrow certainly... tomorrow i have class n i will ask the girl who asked this one to bring this question ALONG WID OPTIONS.... :)
till then. hold on.....:)

1
Swetha Kaushik ·

hey this looks like good question.. can u post ur options?

1
apoorva ·

well....if u want the solution for this..then ,
multiply eqn 1 by a' and 2 by a....and then eliminate t2....ull get the equation in terms of t ....get the value of t....put it in either of equations...and from there ull get the eqn of a parabola....and get 4a value from there....

1
skygirl ·

...and very sadly i will end up getting 3 marks in a paper of 81 if at all i find the correct length of latus rectum (or else i will be 'awarded' -1)...
dat is always a method apoo.... i am sorry dear... i wanted a shorter method but i still dun have the options so sorry to all of you :(

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