is the answer... b2b1=a2a1.. just a guess....
If the lines a1x+b1y+c1=0; a2x+b2y+c2=0 cut the coordinate axes in concylic pts , then give the relation between a1,a2,b1,b2
I think this qn shud be done in 2mins but i cant do it ,still i cant get ne desired results. pls post ur ans.
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sankaara, let them cut in A,B,C,D. then use the fact that the opposite angles of a cylcic quadrilateral are supplementary.
tan(a+(90-θ))=0
or tanα+tan(90-θ)=0
tana+cotθ=0
tana=-a1/b1
cotθ=b2/a2
tana+cotθ=0
-a1/b1+b2/a2=0
b2/a2=a1/b1
b2b1=a1a2
actually this qn is from mtg IITJEE explorer i rate this as an aieee type qn.wont this is an aieee type qn
agar substitute karlo a1=2 a2=3 aur b1=1 b2=6 tho bahut aasan hain ho jaayega
since ABDC are oncyclic..
therefore
OB*OC=OA*OD .... (properties of circle)
this also gives answer in one line...
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