on patial differentiation of given eq we get the eq of 2 lines represented in eq
1. hy+f=0
2. hx+g=0
so x,y intercepts are -g/h,-f/h respectivly
also clerly the lines r perpend.
so area of rectangle formed =length * breadth
=(-g/h)*(-f/h)=fg/h2
if eqn 2hxy +2gx+2fy+c=0 represents 2 st. lines show that they form a rectangle of area mod(fg)/h2 with axes
on patial differentiation of given eq we get the eq of 2 lines represented in eq
1. hy+f=0
2. hx+g=0
so x,y intercepts are -g/h,-f/h respectivly
also clerly the lines r perpend.
so area of rectangle formed =length * breadth
=(-g/h)*(-f/h)=fg/h2