The equation of bisector of internal angleA of the triangle ABC The equation of whose sides are
AB:x+y=1
BC:7X-Y=15AND
AC:x-y=1
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UP 0 DOWN 0 0 1
1 Answers
Lokesh Verma
·2008-12-20 11:48:02
AB: x+y=1
AC:x-y=1
A=(1,0)
The bisectors of this line are clearly x=1 and y=0
Now do some graph plotting .. and u can solve this problem without worrying about all those tricks!