plainly do it by applying formula
2A(p)=p^3-p+1
A(min)=A(1/√3)
If A(1,p2) , B(0,1), C(p,0) are the co-ordinates of the three points then the value of p for which the area of the triangle ABC is minimum is :
A) 1/√3
B) - 1/√3
C) 1/√3 or -1/√3
D) None of these
Ans: D
-
UP 0 DOWN 0 0 2
2 Answers
Anirudh Kumar
·2010-02-05 06:10:13
akari you seem to have made small mistake.
area(p)= p3-p+1
minimum occurs at p=1/2