It is also similar.
The circle touches y axis at origin => It's center lies on x axis. So eqaution of any such circle will be (x-t)2+y2 = t2. Now it passes through (a,b). Eliminate ' t ' to obtain answer!
find the equation to the circle which touches the y-axis at origin and passes through the point (a,b).
It is also similar.
The circle touches y axis at origin => It's center lies on x axis. So eqaution of any such circle will be (x-t)2+y2 = t2. Now it passes through (a,b). Eliminate ' t ' to obtain answer!