circles

Thnx b555....another method....

Line intersects Bigger Circle @ X(p,q) & smaller one @ A(0,2) & B(2,0).....

Take Line XAB ; use section formula

0 = 1*2 + 2√2p => p=-1/√2
2= 2√2q/(1+2√2) => q= 2+1/√2

Radius = √(p²+q²) = √(5+2√2)

am getting its radius = 2+ 4√2

hmm the answers given radius = √5+2√2 and i got the radius to be 2+1/√2

U did using figure kya ??? Similarity of triangles ?.....i found my fault ;trying another way....

solution:

u get the points on smaller corcle and on line as (2,0) and(0,2)

now let the points on line as well as bigger circle be (x1,y1) and (x2,y2)

now use the fact that

(2-x1)²+(-y1)²=1

x1+y1=2 to get x1 and y1

now use x1²+y1²=k² where k is radius u get k as √(5+2√2)

here i have assumed the point towards (2,0) side is(x1,y1)

hope u get it