circles..

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CIrcle C (r=1) touches X axis at A.Centre Q of C lies in Quad I.Tangent from origin touches C at T and P lies on it such that OAP is rt triangle (at A).perimeter =8

Q1 Find PQ
Q2 eqn of circle
Q3 eqn of tangent

here is fig...plz give hints or soln..

#Mathematics #Co-ordinate Geometry

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2 Answers

eragon24 _Retired ·2010-01-26 06:15:03

OA=OT=a
PT=b
PQ=x
QA=1
since perimetr=8
so a+b+x+1+a=8..............i

anle QOA=angle QOT=Î²

so tan2Î²=x+1a........ii

tanÎ²=1/a...........................iii

b=âˆš(x²-1).............iv

triangle PTQ is similar to triangle POA

SO a+bx=a1........v

now solve

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eureka123 ·2010-01-26 10:07:02

thx...trying now...[1]

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circles..

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