isko
x/a +y/b ki form mein likh le
u will get
x+y/5=k/5
iska matlab its intercepts on x axis and y axis r 1 and 1/5 repectively andcompering it with the standard equation u will get k=5
and hence ur answer [1]
The foot of the perpendicular on the line 5x+y=k drawn from the origin is M the line cuts the co-ordinate axes at A and B respectively then BM:MA is
a)5:1
b)15:1
c)25:1
d)2:1
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7 Answers
Mani Pal Singh
·2009-03-23 21:36:42
Mani Pal Singh
·2009-03-23 22:14:57
hey amit thats not the complete solution
i never said that answer is A
u have to find it urself
that was just a HINT
Mani Pal Singh
·2009-03-23 23:57:40
SO
LET IT CUT AT POINTS (M,N)
NOW USE SECTION FORMULA
LET THEY DIVIDE EACH OTHER IN RATIO m/n
SO
m/m+n=M
5n/m+n=N
5A/B=m/n
and we can infer that m/n will be 1/5
so
BM/AM=1/25
HENCE C